determine the name of each compound. use roman numerals where needed. spelling counts. cuo: cu₂o: cos…

Explanation:

Step1: Identify copper oxidation state in CuO

Oxygen has an oxidation - state of - 2. In CuO, for the compound to be neutral, copper has an oxidation state of + 2. So it is copper(II) oxide.

Step2: Identify copper oxidation state in Cu₂O

In Cu₂O, oxygen has an oxidation state of - 2. Let the oxidation state of copper be (x). Using the formula (2x+( - 2)=0), we get (x = + 1). So it is copper(I) oxide.

Step3: Identify cobalt oxidation state in CoS

Sulfur has an oxidation state of - 2. For CoS to be neutral, cobalt has an oxidation state of + 2. So it is cobalt(II) sulfide.

Step4: Identify cobalt oxidation state in Co₂S₃

Sulfur has an oxidation state of - 2. Let the oxidation state of cobalt be (x). Using the formula (2x+3\times(-2)=0), we solve for (x): (2x - 6 = 0), so (x = + 3). So it is cobalt(III) sulfide.

Step5: Identify iron oxidation state in FeBr₂

Bromine has an oxidation state of - 1. For FeBr₂ to be neutral, iron has an oxidation state of + 2. So it is iron(II) bromide.

Answer:

CuO: copper(II) oxide Cu₂O: copper(I) oxide CoS: cobalt(II) sulfide Co₂S₃: cobalt(III) sulfide FeBr₂: iron(II) bromide