determine the number of particles in the 3.20 mol sample of kno3. 1 mol kno3 = 6.02 x 10^23 particles kno3…

determine the number of particles in the 3.20 mol sample of kno3. 1 mol kno3 = 6.02 x 10^23 particles kno3 3.20 mol kno3 = ? x 10^? particles kno3 enter the coefficient in the green box and the exponent in the yellow box. round your coefficient to two decimal places.

determine the number of particles in the 3.20 mol sample of kno3. 1 mol kno3 = 6.02 x 10^23 particles kno3 3.20 mol kno3 = ? x 10^? particles kno3 enter the coefficient in the green box and the exponent in the yellow box. round your coefficient to two decimal places.

Answer

Answer:

1.93, 24

Explanation:

Step1: Set up the proportion

We know that 1 mol of $KNO_3$ has $6.02\times 10^{23}$ particles. Let $x$ be the number of particles in 3.20 mol of $KNO_3$. The proportion is $\frac{x}{3.20\ mol}=\frac{6.02\times 10^{23}\ particles}{1\ mol}$.

Step2: Solve for $x$

$x = 3.20\times6.02\times 10^{23}$ particles. First, calculate $3.20\times6.02 = 19.264$. Then $x=19.264\times 10^{23}$ particles. In scientific - notation, $x = 1.9264\times 10^{24}$ particles. Rounding the coefficient to two decimal places, we get $1.93\times 10^{24}$ particles. So the coefficient is 1.93 and the exponent is 24.