1. determine the percentage composition of al2(co2)3.

Explanation:

Step1: Calculate molar mass of Al₂(CO₃)₃

Molar mass of Al = 26.98 g/mol, C = 12.01 g/mol, O = 16.00 g/mol. Molar mass of Al₂(CO₃)₃ = 2×26.98+3×(12.01 + 3×16.00)= 233.99 g/mol

Step2: Calculate percentage of Al

Mass of Al in Al₂(CO₃)₃ = 2×26.98 = 53.96 g/mol % of Al=$\frac{53.96}{233.99}\times100%\approx23.06%$

Step3: Calculate percentage of C

Mass of C in Al₂(CO₃)₃ = 3×12.01 = 36.03 g/mol % of C=$\frac{36.03}{233.99}\times100%\approx15.39%$

Step4: Calculate percentage of O

Mass of O in Al₂(CO₃)₃ = 3×3×16.00 = 144.00 g/mol % of O=$\frac{144.00}{233.99}\times100%\approx61.53%$

Answer:

Percentage of Al is approximately 23.06%, percentage of C is approximately 15.39%, percentage of O is approximately 61.53%