drag each number to the correct location on the equation. each number can be used more than once, but not…

drag each number to the correct location on the equation. each number can be used more than once, but not all numbers will be used. balance the equation with the correct coefficients. 2 3 4 5 sio₂ + hf → sif₄ + h₂o

drag each number to the correct location on the equation. each number can be used more than once, but not all numbers will be used. balance the equation with the correct coefficients. 2 3 4 5 sio₂ + hf → sif₄ + h₂o

Answer

Answer:

$SiO_2 + 4HF \rightarrow SiF_4+2H_2O$

Explanation:

Step1: Balance fluorine atoms

On the right - hand side, there are 4 fluorine atoms in $SiF_4$. So we put a 4 in front of $HF$ on the left - hand side: $SiO_2 + 4HF \rightarrow SiF_4+H_2O$.

Step2: Balance hydrogen and oxygen atoms

After putting 4 in front of $HF$, we have 4 hydrogen atoms on the left. On the right - hand side, to balance the hydrogen atoms, we put a 2 in front of $H_2O$. Also, the oxygen atoms are balanced as we have 2 oxygen atoms on both sides. So the balanced equation is $SiO_2 + 4HF \rightarrow SiF_4+2H_2O$.