drag each number to the correct location on the equation. each number can be used more than once, but not…

drag each number to the correct location on the equation. each number can be used more than once, but not all numbers will be used. balance the equation with the correct coefficients. 2 3 4 5 kclo3 → kcl + o2

drag each number to the correct location on the equation. each number can be used more than once, but not all numbers will be used. balance the equation with the correct coefficients. 2 3 4 5 kclo3 → kcl + o2

Answer

Explanation:

Step1: Balance oxygen atoms

We know that in $KClO_3$, there are 3 oxygen - atoms and in $O_2$ there are 2 oxygen - atoms. The least common multiple of 3 and 2 is 6. So we put a 2 in front of $KClO_3$ and a 3 in front of $O_2$: $2KClO_3\rightarrow KCl + 3O_2$.

Step2: Balance potassium and chlorine atoms

After step 1, we have 2 potassium and 2 chlorine atoms on the left - hand side. So we put a 2 in front of $KCl$ to balance the equation: $2KClO_3\rightarrow2KCl + 3O_2$.

Answer:

The coefficients are 2, 2, 3 (from left - to - right for $KClO_3$, $KCl$, $O_2$ respectively).