drag the tiles to the correct boxes to complete the pairs. chromium is a transition metal, and oxygen has an…

drag the tiles to the correct boxes to complete the pairs. chromium is a transition metal, and oxygen has an oxidation number of -2. use this information to match each compound to its chemical formula. chromium(vi) oxide chromium(iv) oxide chromium(iii) oxide chromium(ii) oxide cro cro2 cro3 cr2o3

drag the tiles to the correct boxes to complete the pairs. chromium is a transition metal, and oxygen has an oxidation number of -2. use this information to match each compound to its chemical formula. chromium(vi) oxide chromium(iv) oxide chromium(iii) oxide chromium(ii) oxide cro cro2 cro3 cr2o3

Answer

Answer:

  • CrO → chromium(II) oxide
  • CrO₂ → chromium(IV) oxide
  • CrO₃ → chromium(VI) oxide
  • Cr₂O₃ → chromium(III) oxide

Explanation:

Step1: Determine oxidation - state balance

In a compound, the sum of oxidation numbers of all atoms is zero. For CrO, let the oxidation number of Cr be (x). Oxygen has an oxidation number of - 2. So (x+( - 2)=0), then (x = + 2), which is chromium(II) oxide.

Step2: For CrO₂

Let the oxidation number of Cr be (x). There are 2 oxygen atoms each with an oxidation number of - 2. So (x+2\times(-2)=0), (x - 4 = 0), (x=+4), which is chromium(IV) oxide.

Step3: For CrO₃

Let the oxidation number of Cr be (x). There are 3 oxygen atoms each with an oxidation number of - 2. So (x + 3\times(-2)=0), (x-6 = 0), (x = + 6), which is chromium(VI) oxide.

Step4: For Cr₂O₃

Let the oxidation number of Cr be (x). There are 2 Cr atoms and 3 oxygen atoms with an oxidation number of - 2. So (2x+3\times(-2)=0), (2x-6 = 0), (2x=6), (x = + 3), which is chromium(III) oxide.