drag the tiles to the correct boxes. not all tiles will be used. the oxidation number of oxygen is -2, and…
drag the tiles to the correct boxes. not all tiles will be used. the oxidation number of oxygen is -2, and that of chlorine is -1. use this information to match the names of the compounds to their chemical formulas. manganese(ii) chloride manganese(iv) chloride manganese(ii) oxide manganese(iv) oxide mncl₂ mno₂
Answer
Explanation:
Step1: Determine Mn oxidation in MnCl₂
Let oxidation number of Mn be $x$. In $MnCl_{2}$, since each Cl has oxidation number - 1 and compound is neutral, $x+2\times(- 1)=0$. Solving for $x$ gives $x = + 2$. So it is manganese(II) chloride.
Step2: Determine Mn oxidation in MnO₂
Let oxidation number of Mn be $y$. In $MnO_{2}$, since each O has oxidation number - 2 and compound is neutral, $y + 2\times(-2)=0$. Solving for $y$ gives $y=+4$. So it is manganese(IV) oxide.
Answer:
$MnCl_{2}$ → manganese(II) chloride $MnO_{2}$ → manganese(IV) oxide