what is the electron configuration for na+?\n1s²2s²2p⁶3s²\n1s²2s²2p⁶\n1s²2s²2p⁶3s¹\n1s²2s²

Brief Explanations:

Sodium (Na) has an atomic number of 11, with electron configuration $1s^{2}2s^{2}2p^{6}3s^{1}$. $Na^{+}$ is formed when sodium loses one electron. The lost electron is from the outermost shell, which is the 3s orbital. So the electron - configuration of $Na^{+}$ is $1s^{2}2s^{2}2p^{6}$.

Answer:

$1s^{2}2s^{2}2p^{6}$