the electron configuration of nitrogen (n) is\n1s²2s²2p³\n1s²2s²2p⁴\n1s²2s²2p⁵\n1s²2s²2p⁶

Explanation:

Step1: Recall nitrogen's atomic number

Nitrogen has atomic number 7, so it has 7 electrons.

Step2: Fill electron - shells

The first shell (n = 1) can hold 2 electrons with the configuration $1s^{2}$. The second shell (n = 2) has sub - shells s and p. The 2s sub - shell can hold 2 electrons ($2s^{2}$), and the remaining 3 electrons go into the 2p sub - shell ($2p^{3}$). So the electron configuration is $1s^{2}2s^{2}2p^{3}$.

Answer:

$1s^{2}2s^{2}2p^{3}$ (corresponding to the first option)