which is the electronic configuration for oxygen?\n1s²2s²2p¹\n1s²2s²2p³\n1s²2s²2p⁴\n1s²2s²2p⁶

Answer:

$1s^{2}2s^{2}2p^{4}$

Explanation:

Step1: Determine atomic number of oxygen

Oxygen has atomic number 8.

Step2: Fill orbitals according to Aufbau principle

First fill 1s with 2 electrons ($1s^{2}$), then 2s with 2 electrons ($2s^{2}$), and then 2p. Since 2 + 2 = 4 electrons are already filled, we need to fill 4 more in 2p, so it's $2p^{4}$. Overall, it's $1s^{2}2s^{2}2p^{4}$.