what element is shown in the electron configuration below? 1s²2s²2p⁶3s²3p⁶4s²3d¹⁰4p⁶5s¹\no cesium\no…
what element is shown in the electron configuration below? 1s²2s²2p⁶3s²3p⁶4s²3d¹⁰4p⁶5s¹\no cesium\no rubidium\no strontium\no potassium
Answer
Explanation:
Step1: Calculate total electrons
Add up the exponents. $2 + 2+6 + 2+6+2 + 10+6+1=37$.
Step2: Identify element by atomic number
The atomic number is equal to the number of electrons in a neutral atom. The element with atomic number 37 is Rubidium.
Answer:
Rubidium