what is the empirical formula for a compound if a sample contains 1.0 g of s and 1.5 g of o?\nso\nso₃\ns₂o₂\n…

Answer:

B. SO₃

Explanation:

Step1: Calculate moles of S

$n_{S}=\frac{m_{S}}{M_{S}}=\frac{1.0\ g}{32.07\ g/mol}\approx0.0312\ mol$

Step2: Calculate moles of O

$n_{O}=\frac{m_{O}}{M_{O}}=\frac{1.5\ g}{16.00\ g/mol}= 0.09375\ mol$

Step3: Find mole - ratio

$\frac{n_{O}}{n_{S}}=\frac{0.09375\ mol}{0.0312\ mol}\approx3$ The ratio of O to S is 3:1, so the empirical formula is SO₃.