what is the empirical formula for a compound if a sample contains 1.0 g of s and 1.5 g of o?\nso\nso3\ns2o2\n…

Explanation:

Step1: Calculate moles of S

Molar mass of S is 32 g/mol. Moles of S = $\frac{1.0\ g}{32\ g/mol}= 0.03125\ mol$.

Step2: Calculate moles of O

Molar mass of O is 16 g/mol. Moles of O = $\frac{1.5\ g}{16\ g/mol}=0.09375\ mol$.

Step3: Find mole - ratio

Divide each number of moles by the smaller number of moles (0.03125 mol). For S: $\frac{0.03125\ mol}{0.03125\ mol}=1$. For O: $\frac{0.09375\ mol}{0.03125\ mol}=3$.

Answer:

SO₃