for the equation 3cu + 8hno₃ → 3cu(no₃)₂ + 2no + 4h₂o, how many units of no₃ are represented on the products…
for the equation 3cu + 8hno₃ → 3cu(no₃)₂ + 2no + 4h₂o, how many units of no₃ are represented on the products side?\n2\n3\n6\n8
Answer
Explanation:
Step1: Identify nitrate - containing product
The nitrate - containing product is $3Cu(NO_3)_2$.
Step2: Calculate number of $NO_3$ units
In one unit of $Cu(NO_3)_2$, there are 2 units of $NO_3$. Since we have 3 units of $Cu(NO_3)_2$, the number of $NO_3$ units is $3\times2 = 6$.
Answer:
6