for the equation 3cu + 8hno₃ → 3cu(no₃)₂ + 2no + 4h₂o, how many units of no₃ are represented on the products…
for the equation 3cu + 8hno₃ → 3cu(no₃)₂ + 2no + 4h₂o, how many units of no₃ are represented on the products side?\no 2\no 3\no 6\no 8
Answer
Explanation:
Step1: Identify the product with $NO_3$
The product with $NO_3$ is $3Cu(NO_3)_2$.
Step2: Calculate number of $NO_3$ units
In $Cu(NO_3)_2$, there are 2 $NO_3$ groups per formula - unit. And there are 3 moles of $Cu(NO_3)_2$. So the number of $NO_3$ units is $3\times2 = 6$.
Answer:
6