for the equation bacl₂ + na₂so₄ → baso₄ + 2nacl, how many chlorine atoms are on the reactants side and on…

for the equation bacl₂ + na₂so₄ → baso₄ + 2nacl, how many chlorine atoms are on the reactants side and on the products side?\nreactants: 1; products: 1\nreactants: 1; products: 2\nreactants: 2; products: 1\nreactants: 2; products: 2

for the equation bacl₂ + na₂so₄ → baso₄ + 2nacl, how many chlorine atoms are on the reactants side and on the products side?\nreactants: 1; products: 1\nreactants: 1; products: 2\nreactants: 2; products: 1\nreactants: 2; products: 2

Answer

Explanation:

Step1: Count chlorine atoms in reactants

In $BaCl_2$, there are 2 chlorine atoms and $Na_2SO_4$ has 0 chlorine atoms. So total 2 chlorine atoms on reactants side.

Step2: Count chlorine atoms in products

In $2NaCl$, the coefficient 2 means there are 2 chlorine atoms and $BaSO_4$ has 0 chlorine atoms. So total 2 chlorine atoms on products side.

Answer:

D. reactants: 2; products: 2