is the equation balanced? 2h₂o + o₂ --> 4mgo + 3fe

Answer:

No

Explanation:

Step1: Count hydrogen atoms

Left - hand side: In $2H_2O$, number of $H$ atoms is $2\times2 = 4$. Right - hand side: There are no $H$ atoms.

Step2: Count oxygen atoms

Left - hand side: In $2H_2O$ there are 2 $O$ atoms and in $O_2$ there are 2 $O$ atoms, total 4 $O$ atoms. Right - hand side: In $4MgO$ there are 4 $O$ atoms, but the presence of $Fe$ is also not balanced with respect to the left - hand side elements. Also, $Mg$ and $Fe$ are not present on the left - hand side in the given form. The equation is not balanced as elements and their numbers on both sides do not match.