the equation for the ph of a substance is ph = -logh+, where h+ is the concentration of hydrogen ions. a…

Explanation:

Step1: Find $[H^+]$ for basic solution

Given $pH = -\log[H^+]$, for $pH = 11.2$, we have $11.2=-\log[H^+]$. Then $\log[H^+]= - 11.2$, and $[H^+]_{basic}=10^{-11.2}$.

Step2: Find $[H^+]$ for acidic solution

For $pH = 2.4$, we have $2.4 = -\log[H^+]$. Then $\log[H^+]=-2.4$, and $[H^+]_{acidic}=10^{-2.4}$.

Step3: Calculate the difference

$[H^+]{acidic}-[H^+]{basic}=10^{-2.4}-10^{-11.2}$. Since $10^{-11.2}$ is much smaller than $10^{-2.4}$, we can approximate the difference as $10^{-2.4}\approx 3.98\times10^{-3}\approx4.0\times 10^{-3}$.

Answer:

$4.0\times 10^{-3}$