the equation below shows hydrogen reacting with oxygen to produce water.\n2h₂ + o₂ → 2h₂o\nif 16 mol of…

the equation below shows hydrogen reacting with oxygen to produce water.\n2h₂ + o₂ → 2h₂o\nif 16 mol of oxygen were reacted with excess hydrogen gas, how many moles of water would be produced?\n4.0 mol\n8.0 mol\n16 mol\n32 mol

the equation below shows hydrogen reacting with oxygen to produce water.\n2h₂ + o₂ → 2h₂o\nif 16 mol of oxygen were reacted with excess hydrogen gas, how many moles of water would be produced?\n4.0 mol\n8.0 mol\n16 mol\n32 mol

Answer

Explanation:

Step1: Identify mole - ratio

From the balanced equation $2H_2 + O_2\rightarrow2H_2O$, the mole - ratio of $O_2$ to $H_2O$ is 1:2.

Step2: Calculate moles of water

Given 16 mol of $O_2$. Since the mole - ratio of $O_2$ to $H_2O$ is 1:2, the moles of $H_2O$ produced is $n_{H_2O}=2\times n_{O_2}$. Substituting $n_{O_2} = 16$ mol, we get $n_{H_2O}=2\times16$ mol.

Answer:

32 mol