the equation below shows hydrogen reacting with oxygen to produce water.\n2h₂ + o₂ → 2h₂o\nif 16 mol of…

the equation below shows hydrogen reacting with oxygen to produce water.\n2h₂ + o₂ → 2h₂o\nif 16 mol of oxygen were reacted with excess hydrogen gas, how many moles of water would be produced?\no 4.0 mol\no 8.0 mol\no 16 mol\no 32 mol

the equation below shows hydrogen reacting with oxygen to produce water.\n2h₂ + o₂ → 2h₂o\nif 16 mol of oxygen were reacted with excess hydrogen gas, how many moles of water would be produced?\no 4.0 mol\no 8.0 mol\no 16 mol\no 32 mol

Answer

Explanation:

Step1: Identify mole - ratio

From the balanced equation $2H_2 + O_2\rightarrow2H_2O$, the mole - ratio of $O_2$ to $H_2O$ is $1:2$.

Step2: Calculate moles of water

If $n(O_2)=16$ mol, and $\frac{n(H_2O)}{n(O_2)} = 2$ (from the mole - ratio), then $n(H_2O)=2\times n(O_2)$. $n(H_2O)=2\times16$ mol $ = 32$ mol

Answer:

D. 32 mol