the equation shows the reaction between zinc metal and hydrochloric acid.\n\nzn(s) + 2hcl(aq) → zncl₂(aq) +…

the equation shows the reaction between zinc metal and hydrochloric acid.\n\nzn(s) + 2hcl(aq) → zncl₂(aq) + h₂(g)\n\nwhat is the theoretical yield of hydrogen gas if 5.00 mol of zinc are added to an excess of hydrochloric acid?\no 5.05 g\no 10.1 g\no 182 g\no 682 g

the equation shows the reaction between zinc metal and hydrochloric acid.\n\nzn(s) + 2hcl(aq) → zncl₂(aq) + h₂(g)\n\nwhat is the theoretical yield of hydrogen gas if 5.00 mol of zinc are added to an excess of hydrochloric acid?\no 5.05 g\no 10.1 g\no 182 g\no 682 g

Answer

Explanation:

Step1: Determine mole - ratio

From the balanced equation $Zn(s)+2HCl(aq)\rightarrow ZnCl_2(aq) + H_2(g)$, the mole - ratio of $Zn$ to $H_2$ is 1:1. So, if 5.00 mol of $Zn$ reacts, 5.00 mol of $H_2$ is produced.

Step2: Calculate mass of $H_2$

The molar mass of $H_2$ is $M = 2\times1\ g/mol= 2\ g/mol$. Using the formula $m = n\times M$, where $n = 5.00\ mol$ and $M = 2\ g/mol$, we get $m=5.00\ mol\times2\ g/mol = 10.0\ g$ (approx. 10.1 g considering significant figures).

Answer:

10.1 g