2) for this exercise, we will work with a different rate called molarity (m). this is a way to measure…

2) for this exercise, we will work with a different rate called molarity (m). this is a way to measure concentration; the units are mols/l. for this scatter graph, i want you to plot how many moles you have at 5 different volumes 10 nl, 37μl, 448 μl, 12 ml, and 2.4 l of a solution that is 0.63m. think of an equation that could tell you how many moles you have in each volume, and then plot the moles on the y - axis and volume on the x - axis. also, make a second plot where you plot the number of molecules per volume. you will also need avogadro’s number in this formula (6.02 x 10^23). use scientific notation for molecules on this graph (review the slides from lecture 1 for reference). be sure to label your axis and add a trend line with a formula; this formula should match the formula you used to calculate the number of moles and the number of molecules.\nchem. 23 lab 2 introduction to quantitative analysis

2) for this exercise, we will work with a different rate called molarity (m). this is a way to measure concentration; the units are mols/l. for this scatter graph, i want you to plot how many moles you have at 5 different volumes 10 nl, 37μl, 448 μl, 12 ml, and 2.4 l of a solution that is 0.63m. think of an equation that could tell you how many moles you have in each volume, and then plot the moles on the y - axis and volume on the x - axis. also, make a second plot where you plot the number of molecules per volume. you will also need avogadro’s number in this formula (6.02 x 10^23). use scientific notation for molecules on this graph (review the slides from lecture 1 for reference). be sure to label your axis and add a trend line with a formula; this formula should match the formula you used to calculate the number of moles and the number of molecules.\nchem. 23 lab 2 introduction to quantitative analysis

Answer

Explanation:

Step1: Recall molarity formula

The formula for molarity is $M=\frac{n}{V}$, where $M$ is molarity, $n$ is the number of moles, and $V$ is the volume in liters. We can re - arrange it to $n = M\times V$. The molarity $M = 0.63M$.

Step2: Convert volumes to liters

  • $V_1=10nL = 10\times10^{-9}L=1\times10^{-8}L$
  • $V_2 = 37\mu L=37\times10^{- 6}L$
  • $V_3 = 448\mu L=448\times10^{-6}L = 4.48\times10^{-4}L$
  • $V_4=12mL = 12\times10^{-3}L$
  • $V_5 = 2.4L$

Step3: Calculate number of moles for each volume

  • $n_1 = M\times V_1=0.63\times1\times10^{-8}=6.3\times10^{-9}$ moles
  • $n_2 = M\times V_2=0.63\times37\times10^{-6}=2.331\times10^{-5}$ moles
  • $n_3 = M\times V_3=0.63\times4.48\times10^{-4}=2.8224\times10^{-4}$ moles
  • $n_4 = M\times V_4=0.63\times12\times10^{-3}=7.56\times10^{-3}$ moles
  • $n_5 = M\times V_5=0.63\times2.4 = 1.512$ moles

Step4: Calculate number of molecules

The number of molecules $N=n\times N_A$, where $N_A = 6.02\times10^{23}$ molecules/mol.

  • $N_1=n_1\times N_A=6.3\times10^{-9}\times6.02\times10^{23}=3.7926\times10^{15}$ molecules
  • $N_2=n_2\times N_A=2.331\times10^{-5}\times6.02\times10^{23}=1.403262\times10^{19}$ molecules
  • $N_3=n_3\times N_A=2.8224\times10^{-4}\times6.02\times10^{23}=1.6990848\times10^{20}$ molecules
  • $N_4=n_4\times N_A=7.56\times10^{-3}\times6.02\times10^{23}=4.55112\times10^{21}$ molecules
  • $N_5=n_5\times N_A=1.512\times6.02\times10^{23}=9.09224\times10^{23}$ molecules

To plot:

  • For the first plot (moles vs volume), plot the points $(V_1,n_1),(V_2,n_2),(V_3,n_3),(V_4,n_4),(V_5,n_5)$ with volume on the x - axis and moles on the y - axis. The trend line formula is $y = 0.63x$ (since $n = 0.63V$).
  • For the second plot (number of molecules vs volume), plot the points $(V_1,N_1),(V_2,N_2),(V_3,N_3),(V_4,N_4),(V_5,N_5)$ with volume on the x - axis and number of molecules on the y - axis. The trend line formula is $y=0.63\times6.02\times10^{23}x=3.7926\times10^{23}x$.

Answer:

Moles: $6.3\times10^{-9},2.331\times10^{-5},2.8224\times10^{-4},7.56\times10^{-3},1.512$ Molecules: $3.7926\times10^{15},1.403262\times10^{19},1.6990848\times10^{20},4.55112\times10^{21},9.09224\times10^{23}$