experiment #2\nbased on the law of conservation of mass, predict the minimum amount of magnesium that will…

experiment #2\nbased on the law of conservation of mass, predict the minimum amount of magnesium that will react with all 16.0 grams of oxygen to produce 40.3 grams of magnesium oxide.\nmagnesium + oxygen -----> magnesium oxide\n□g + 16.0 g ----> 40.3 g\nexperiment #3 assuming that magnesium and oxygen will react completely with one another, predict the mass of magnesium oxide that will be produced.\nmagnesium + oxygen -----> magnesium oxide\n12.2 g + 8.0 g ----> □g

experiment #2\nbased on the law of conservation of mass, predict the minimum amount of magnesium that will react with all 16.0 grams of oxygen to produce 40.3 grams of magnesium oxide.\nmagnesium + oxygen -----> magnesium oxide\n□g + 16.0 g ----> 40.3 g\nexperiment #3 assuming that magnesium and oxygen will react completely with one another, predict the mass of magnesium oxide that will be produced.\nmagnesium + oxygen -----> magnesium oxide\n12.2 g + 8.0 g ----> □g

Answer

Explanation:

Step1: Apply the Law of Conservation of Mass for Experiment #2

According to the law, mass of reactants = mass of products. Let the mass of magnesium be $x$. So $x + 16.0=40.3$.

Step2: Solve for the mass of magnesium

$x=40.3 - 16.0$. $x = 24.3$ g.

Step3: Apply the Law of Conservation of Mass for Experiment #3

The mass of magnesium oxide produced is the sum of the mass of magnesium and oxygen. Mass of magnesium = 12.2 g, mass of oxygen = 8.0 g. So mass of magnesium oxide = $12.2+8.0$.

Step4: Calculate the mass of magnesium oxide

$12.2 + 8.0=20.2$ g.

Answer:

Experiment #2: 24.3 g Experiment #3: 20.2 g