an experimental procedure requires 10 ml of acid to be dissolved into a beaker of water. an additional 5 ml…

Answer:

C. the concentration of acid in the solution has been increased

Explanation:

Step1: Recall the formula for concentration

Concentration of a solute (acid in this case) in a solution is given by (C=\frac{n}{V}) (where (n) is the amount of solute and (V) is the volume of the solution). Here, we can consider the volume of acid as a measure of the amount of solute (assuming the acid is a pure substance for simplicity).

Step2: Analyze the change

Initially, we have (n_1 = 10\space ml) of acid. After adding (5\space ml) more acid, (n_2=10 + 5=15\space ml) of acid. The volume of the solution (V) (water + acid) will increase slightly (since we add acid to water), but the increase in the amount of solute ((\Delta n=5\space ml)) is significant. Using the formula (C=\frac{n}{V}), when (n) increases (and (V) increases by a relatively smaller proportion, because we add a small amount of acid to a beaker of water), the value of (C) (concentration) increases.

• Option A: “Strength” is a vague term. In chemistry, we use concentration.
• Option B: Since (n) increases, concentration does not decrease.
• Option D: Again, “strength” is not the correct term, and concentration increases not decreases.