fill in the blanks with the total number of valence electrons that must be considered for the lewis…

fill in the blanks with the total number of valence electrons that must be considered for the lewis structure of each molecule and ion shown.\n• hcp=\n• sh₃⁺=\n• c₂h₃o₂⁻=

fill in the blanks with the total number of valence electrons that must be considered for the lewis structure of each molecule and ion shown.\n• hcp=\n• sh₃⁺=\n• c₂h₃o₂⁻=

Answer

Explanation:

Step1: Determine valence - electrons of each atom in HCP

Hydrogen (H) has 1 valence electron, carbon (C) has 4 valence electrons, and phosphorus (P) has 5 valence electrons. So for HCP, the total number of valence electrons is (1 + 4+5=10).

Step2: Determine valence - electrons of each atom in (SH_{3}^{+})

Sulfur (S) has 6 valence electrons, hydrogen (H) has 1 valence electron. There are 3 hydrogen atoms and the ion has a + 1 charge (which means one less electron). So the total number of valence electrons is (6+(1\times3)-1 = 8).

Step3: Determine valence - electrons of each atom in (C_{2}H_{3}O_{2}^{-})

Carbon (C) has 4 valence electrons, hydrogen (H) has 1 valence electron, and oxygen (O) has 6 valence electrons. There are 2 carbon atoms, 3 hydrogen atoms, 2 oxygen atoms, and the ion has a - 1 charge (which means one extra electron). So the total number of valence electrons is ((4\times2)+(1\times3)+(6\times2)+1=24).

Answer:

HCP: 10 (SH_{3}^{+}): 8 (C_{2}H_{3}O_{2}^{-}): 24