fill in the gaps to balance the equation. use the smallest set of whole numbers to balance the equation and…
fill in the gaps to balance the equation. use the smallest set of whole numbers to balance the equation and include coefficients of \1\ when appropriate. libr + hpo₃ → lipo₃ + hbr complete the table to determine how many atoms of each element are present in the reactants and products. element reactant products li br h p o
Answer
Explanation:
Step1: Balance Li and Br
Let's start by balancing the lithium (Li) and bromine (Br) atoms. If we put a coefficient of 1 in front of $LiBr$ and $LiPO_3$, and a coefficient of 1 in front of $HBr$, the Li and Br atoms are un - balanced. To balance them, we put a coefficient of 1 in front of $LiBr$ and $LiPO_3$ and a coefficient of 1 in front of $HBr$, we need to adjust. Let's put a coefficient of 1 in front of $HPO_3$ and try to balance the equation. The balanced equation is $LiBr + HPO_3=LiPO_3 + HBr$.
Step2: Count atoms
- Li: In the reactant side, from $LiBr$, the number of Li atoms is 1. In the product side, from $LiPO_3$, the number of Li atoms is 1.
- Br: In the reactant side, from $LiBr$, the number of Br atoms is 1. In the product side, from $HBr$, the number of Br atoms is 1.
- H: In the reactant side, from $HPO_3$, the number of H atoms is 1. In the product side, from $HBr$, the number of H atoms is 1.
- P: In the reactant side, from $HPO_3$, the number of P atoms is 1. In the product side, from $LiPO_3$, the number of P atoms is 1.
- O: In the reactant side, from $HPO_3$, the number of O atoms is 3. In the product side, from $LiPO_3$, the number of O atoms is 3.
Answer:
- $LiBr + 1HPO_3\rightarrow1LiPO_3 + 1HBr$ | Element | Reactant | Products | | ---- | ---- | ---- | | Li | 1 | 1 | | Br | 1 | 1 | | H | 1 | 1 | | P | 1 | 1 | | O | 3 | 3 |