fill out the table below based on the following chemical equation: __rb + __s₈ → __rb₂s\ntotal # before…
fill out the table below based on the following chemical equation: __rb + __s₈ → __rb₂s\ntotal # before (reactants) elements total # after (reactants)\nrb\ns\nthe correct coefficients for the equation is: __rb + __s₈ → __rb₂s
Answer
Explanation:
Step1: Balance sulfur atoms
Let the coefficient of $S_8$ be $x$ and the coefficient of $Rb_2S$ be $y$. For sulfur, we have $8x=y$. To get whole - number coefficients, we can start with $x = 1$, then $y=8$.
Step2: Balance rubidium atoms
If the coefficient of $Rb_2S$ is $8$, then the number of rubidium atoms in the product is $16$. So the coefficient of $Rb$ in the reactant must be $16$.
Answer:
| Total # Before (reactants) | Elements | Total # After (Products) |
|---|---|---|
| 16 | Rb | 16 |
| 8 | S | 8 |
| The correct coefficients for the equation is: 16 $Rb$+ 1 $S_8$→ 8 $Rb_2S$ |