what is the final chemical equation from the following intermediate chemical equations? p4o6(s)→p4(s)+3o2(g)…

what is the final chemical equation from the following intermediate chemical equations? p4o6(s)→p4(s)+3o2(g) p4(s)+5o2(g)→p4o10(s) p4o6(s)+2o2(g)→p4o10(s) p4o6(s)+8o2(g)→2p4(s)+p4o10(s) p4o6(s)+15o2(g)→p4(s)+p4o10(s) p4o6(s)+(5/3)o2(g)→p4o10(s)

what is the final chemical equation from the following intermediate chemical equations? p4o6(s)→p4(s)+3o2(g) p4(s)+5o2(g)→p4o10(s) p4o6(s)+2o2(g)→p4o10(s) p4o6(s)+8o2(g)→2p4(s)+p4o10(s) p4o6(s)+15o2(g)→p4(s)+p4o10(s) p4o6(s)+(5/3)o2(g)→p4o10(s)

Answer

Explanation:

Step1: Add the two given equations

[ \begin{align*} P_4O_6(s)&\rightarrow P_4(s)+3O_2(g)\ P_4(s)+5O_2(g)&\rightarrow P_4O_{10}(s)\ \end{align*} ] Adding them gives (P_4O_6(s)+P_4(s)+ 5O_2(g)\rightarrow P_4(s)+3O_2(g)+P_4O_{10}(s))

Step2: Cancel out common terms

Cancel out (P_4(s)) on both sides of the equation. Also, simplify the oxygen - terms: (5O_2(g)-3O_2(g) = 2O_2(g)). So the final equation is (P_4O_6(s)+2O_2(g)\rightarrow P_4O_{10}(s))

Answer:

(P_4O_6(s)+2O_2(g)\rightarrow P_4O_{10}(s))