what is the final concentration of 500. ml of a solution made from 125. ml of 3.0 m naoh? ? m naoh

Explanation:

Step1: Identify the dilution formula

The dilution formula is $M_1V_1 = M_2V_2$, where $M_1$ is the initial - concentration, $V_1$ is the initial - volume, $M_2$ is the final - concentration, and $V_2$ is the final - volume.

Step2: Assign values to variables

We are given that $M_1 = 3.0\ M$, $V_1=125\ mL$, and $V_2 = 500\ mL$. We need to find $M_2$.

Step3: Rearrange the formula to solve for $M_2$

From $M_1V_1 = M_2V_2$, we can solve for $M_2$ as $M_2=\frac{M_1V_1}{V_2}$.

Step4: Substitute the values into the formula

$M_2=\frac{3.0\ M\times125\ mL}{500\ mL}$. $M_2=\frac{375\ M\cdot mL}{500\ mL}= 0.75\ M$.

Answer:

$0.75$