what is the final concentration of 925 ml of a solution made from 222 ml of 4.5 m hcl?\n? m hcl
what is the final concentration of 925 ml of a solution made from 222 ml of 4.5 m hcl?\n? m hcl
Answer
Explanation:
Step1: Identify the dilution formula
$M_1V_1 = M_2V_2$
Step2: Define the known values
$M_1 = 4.5\ M$, $V_1=222\ mL$, $V_2 = 925\ mL$
Step3: Solve for $M_2$
$M_2=\frac{M_1V_1}{V_2}=\frac{4.5\ M\times222\ mL}{925\ mL}$ $M_2=\frac{999\ M\cdot mL}{925\ mL}\approx1.08\ M$
Answer:
$1.08\ M$