find the number of protons, neutrons, and electrons in the following elements. round atomic masses to whole…

find the number of protons, neutrons, and electrons in the following elements. round atomic masses to whole numbers to do these problems.\n25) pr p = _, n = _, & e = _\n26) v p = _, n = _, & e = _\n27) b p = _, n = _, & e = _\n28) mn p = _, n = _, & e = _\n29) te p = _, n = _, & e = _\n30) i p = _, n = _, & e = _
Answer
Explanation:
Step1: Recall atomic number and basic particle relationships
The atomic number (Z) is equal to the number of protons (p). For a neutral atom, the number of electrons (e) is equal to the number of protons. The number of neutrons (n) is calculated as mass number (A) - atomic number (Z).
Step2: Find particles for Pr (Praseodymium)
Pr has an atomic number of 59. Given mass number is considered as a whole - number for this problem. Let's assume mass number A = 141 (common isotope). p = 59 (from atomic number) n=A - Z = 141 - 59 = 82 e = 59 (for neutral atom)
Step3: Find particles for B (Boron)
B has an atomic number of 5. Assume mass number A = 11 (common isotope). p = 5 n=A - Z = 11 - 5 = 6 e = 5
Step4: Find particles for Te (Tellurium)
Te has an atomic number of 52. Assume mass number A = 128 (common isotope). p = 52 n=A - Z = 128 - 52 = 76 e = 52
Step5: Find particles for V (Vanadium)
V has an atomic number of 23. Assume mass number A = 51 (common isotope). p = 23 n=A - Z = 51 - 23 = 28 e = 23
Step6: Find particles for Mn (Manganese)
Mn has an atomic number of 25. Assume mass number A = 55 (common isotope). p = 25 n=A - Z = 55 - 25 = 30 e = 25
Step7: Find particles for I (Iodine)
I has an atomic number of 53. Assume mass number A = 127 (common isotope). p = 53 n=A - Z = 127 - 53 = 74 e = 53
Answer:
- Pr: p = 59, n = 82, e = 59
- B: p = 5, n = 6, e = 5
- Te: p = 52, n = 76, e = 52
- V: p = 23, n = 28, e = 23
- Mn: p = 25, n = 30, e = 25
- I: p = 53, n = 74, e = 53