a flexible container has 3.75 moles of gas and a volume of 20.0 l. it shrinks to 8.0 l when some gas is…

a flexible container has 3.75 moles of gas and a volume of 20.0 l. it shrinks to 8.0 l when some gas is removed. the pressure and temperature remain the same throughout. how many moles of gas are in the contracted container? n₂ = ? mol
Answer
Explanation:
Step1: Identify the gas - law formula
Since pressure and temperature are constant, we use Avogadro's law $V_1/n_1 = V_2/n_2$.
Step2: Substitute the given values
We know $V_1 = 20.0\ L$, $n_1=3.75\ mol$, and $V_2 = 8.0\ L$. Substituting into the formula gives $\frac{20.0\ L}{3.75\ mol}=\frac{8.0\ L}{n_2}$.
Step3: Solve for $n_2$
Cross - multiply: $20.0\ L\times n_2=8.0\ L\times3.75\ mol$. Then $n_2=\frac{8.0\ L\times3.75\ mol}{20.0\ L}$. $n_2 = 1.5\ mol$.
Answer:
$1.5$