the following balanced equation shows the decomposition of ammonia (nh₃) into nitrogen (n₂) and hydrogen…

the following balanced equation shows the decomposition of ammonia (nh₃) into nitrogen (n₂) and hydrogen (h₂). 2nh₃ → n₂ + 3h₂. a quantity of nh₃ decomposes to produce 0.0351 mol n₂. how many moles of h₂ are produced? 0.0351 mol h₂ 0.0117 mol h₂ 0.105 mol h₂ 0.0702 mol h₂ done

the following balanced equation shows the decomposition of ammonia (nh₃) into nitrogen (n₂) and hydrogen (h₂). 2nh₃ → n₂ + 3h₂. a quantity of nh₃ decomposes to produce 0.0351 mol n₂. how many moles of h₂ are produced? 0.0351 mol h₂ 0.0117 mol h₂ 0.105 mol h₂ 0.0702 mol h₂ done

Answer

Answer:

0.105 mol H₂

Explanation:

Step1: Identify mole - ratio

From the balanced equation (2NH_3\rightarrow N_2 + 3H_2), the mole - ratio of (N_2) to (H_2) is (n_{N_2}:n_{H_2}=1:3).

Step2: Calculate moles of (H_2)

Given (n_{N_2} = 0.0351) mol. Using the mole - ratio, (n_{H_2}=3\times n_{N_2}). So (n_{H_2}=3\times0.0351) mol ( = 0.1053\approx0.105) mol.