the following balanced equation shows the formation of ammonia.\nn₂ + 3h₂ → 2nh₃\nhow many moles of nitrogen…

the following balanced equation shows the formation of ammonia.\nn₂ + 3h₂ → 2nh₃\nhow many moles of nitrogen are needed to completely convert 6.34 mol of hydrogen?\n1.02 mol\n2.11 mol\n12.68 mol\n19.02 mol

the following balanced equation shows the formation of ammonia.\nn₂ + 3h₂ → 2nh₃\nhow many moles of nitrogen are needed to completely convert 6.34 mol of hydrogen?\n1.02 mol\n2.11 mol\n12.68 mol\n19.02 mol

Answer

Explanation:

Step1: Identify mole - ratio

From the balanced equation $N_2 + 3H_2\rightarrow2NH_3$, the mole - ratio of $N_2$ to $H_2$ is $n_{N_2}:n_{H_2}=1:3$.

Step2: Calculate moles of $N_2$

We know $n_{H_2} = 6.34$ mol. Using the mole - ratio, $n_{N_2}=\frac{1}{3}n_{H_2}$. Substitute $n_{H_2}=6.34$ mol into the equation: $n_{N_2}=\frac{1}{3}\times6.34$ mol $= 2.11$ mol.

Answer:

2.11 mol