the following balanced equation shows the formation of ammonia. n2 + 3h2 → 2nh3 how many moles of nitrogen…

the following balanced equation shows the formation of ammonia. n2 + 3h2 → 2nh3 how many moles of nitrogen are needed to completely convert 6.34 mol of hydrogen? 1.02 mol 2.11 mol 12.68 mol 19.02 mol

the following balanced equation shows the formation of ammonia. n2 + 3h2 → 2nh3 how many moles of nitrogen are needed to completely convert 6.34 mol of hydrogen? 1.02 mol 2.11 mol 12.68 mol 19.02 mol

Answer

Answer:

B. 2.11 mol

Explanation:

Step1: Identify mole - ratio

From the balanced equation $N_2 + 3H_2\rightarrow2NH_3$, the mole - ratio of $N_2$ to $H_2$ is 1:3.

Step2: Set up proportion

Let $x$ be the moles of $N_2$. We have the proportion $\frac{x}{6.34}=\frac{1}{3}$.

Step3: Solve for $x$

$x=\frac{6.34\times1}{3}\approx2.11$ mol.