the following balanced equation shows the formation of water. 2h₂ + o₂ → 2h₂o how many moles of oxygen (o₂)…

Explanation:

Step1: Identify mole - ratio

From the balanced equation $2H_2 + O_2\rightarrow2H_2O$, the mole - ratio of $H_2$ to $O_2$ is $2:1$.

Step2: Set up proportion

Let $x$ be the moles of $O_2$. We have the proportion $\frac{2\ mol\ H_2}{1\ mol\ O_2}=\frac{1.67\ mol\ H_2}{x}$.

Step3: Solve for $x$

Cross - multiply: $2x = 1.67\times1$. Then $x=\frac{1.67}{2}=0.835\ mol$.

Answer:

$0.835\ mol\ O_2$