which of the following elements is likely to exhibit metallic bonding in its pure form?\nchlorine…

which of the following elements is likely to exhibit metallic bonding in its pure form?\nchlorine (cl)\npotassium (k)\noxygen (o)\ncarbon (c)\nwhat type of bond is primarily responsible for holding the atoms together within a single molecule of methane (ch₄)?\ncovalent bond\nionic bond\nmetallic bond\nhydrogen bond\nhow does the electron configuration of an atom with a strong tendency to lose electrons (low electronegativity) influence the type of bond it is likely to form?\nit is likely to form ionic bonds by losing electrons to another atom.

which of the following elements is likely to exhibit metallic bonding in its pure form?\nchlorine (cl)\npotassium (k)\noxygen (o)\ncarbon (c)\nwhat type of bond is primarily responsible for holding the atoms together within a single molecule of methane (ch₄)?\ncovalent bond\nionic bond\nmetallic bond\nhydrogen bond\nhow does the electron configuration of an atom with a strong tendency to lose electrons (low electronegativity) influence the type of bond it is likely to form?\nit is likely to form ionic bonds by losing electrons to another atom.

Answer

Brief Explanations:

  1. Metallic bonding occurs in metals. Potassium is a metal, while chlorine, oxygen, and carbon are non - metals. So potassium is likely to exhibit metallic bonding in its pure form.
  2. In methane ($CH_4$), carbon shares electrons with hydrogen atoms. Covalent bonds involve the sharing of electrons between atoms, so the bond within a single methane molecule is a covalent bond.
  3. Atoms with a strong tendency to lose electrons (low electronegativity) often form ionic bonds by transferring electrons to atoms with high electronegativity.

Answer:

  1. Potassium (K)
  2. Covalent bond
  3. It is likely to form ionic bonds by losing electrons to another atom.