this formula equation is unbalanced. bacl₂(aq) + na₂co₃(aq) → baco₃(s) + nacl(aq) which coefficient should…

this formula equation is unbalanced. bacl₂(aq) + na₂co₃(aq) → baco₃(s) + nacl(aq) which coefficient should be placed in front of nacl to balance this equation? 1 2 3 4

this formula equation is unbalanced. bacl₂(aq) + na₂co₃(aq) → baco₃(s) + nacl(aq) which coefficient should be placed in front of nacl to balance this equation? 1 2 3 4

Answer

Explanation:

Step1: Count atoms on reactant side

On the left - hand side, for barium ($Ba$) we have 1 atom, for chlorine ($Cl$) we have 2 atoms, for sodium ($Na$) we have 2 atoms, for carbon ($C$) we have 1 atom and for oxygen ($O$) we have 3 atoms.

Step2: Analyze product side atoms

On the right - hand side, for barium ($Ba$) we have 1 atom, for carbon ($C$) we have 1 atom, for oxygen ($O$) we have 3 atoms. For sodium and chlorine in $NaCl$, currently we have 1 $Na$ and 1 $Cl$ atom.

Step3: Balance the equation

To balance the sodium and chlorine atoms, since we have 2 chlorine atoms on the reactant side and 2 sodium atoms on the reactant side, we need 2 moles of $NaCl$ on the product side. The balanced equation is $BaCl_{2}(aq)+Na_{2}CO_{3}(aq)\rightarrow BaCO_{3}(s) + 2NaCl(aq)$.

Answer:

B. 2