which is the formula mass of (nh4)2so4?\n96.07 amu\n114.12 amu\n116.17 amu\n132.17 amu

Explanation:

Step1: Identify element - counts

$(NH_4)_2SO_4$ has 2 N, 8 H, 1 S, 4 O.

Step2: Find atomic - masses

Atomic mass of N = 14.01 amu, H = 1.01 amu, S = 32.07 amu, O = 16.00 amu.

Step3: Calculate total mass

Mass of N: $2\times14.01 = 28.02$ amu; Mass of H: $8\times1.01 = 8.08$ amu; Mass of S: $1\times32.07 = 32.07$ amu; Mass of O: $4\times16.00 = 64.00$ amu. Total formula mass = $28.02+8.08 + 32.07+64.00=132.17$ amu.

Answer:

132.17 amu