a gas that exerts a pressure of 14 atm sits in a container with a volume of 312 ml. what is the pressure…

a gas that exerts a pressure of 14 atm sits in a container with a volume of 312 ml. what is the pressure when the gas is transferred to a container with a volume of 652 ml? p = ? atm assume that the number of moles and the temperature remain constant.

a gas that exerts a pressure of 14 atm sits in a container with a volume of 312 ml. what is the pressure when the gas is transferred to a container with a volume of 652 ml? p = ? atm assume that the number of moles and the temperature remain constant.

Answer

Explanation:

Step1: Identify the relevant gas - law

Boyle's law states that $P_1V_1 = P_2V_2$ for a given amount of gas at constant temperature.

Step2: Assign values to variables

$P_1 = 14$ atm, $V_1=312$ mL, $V_2 = 652$ mL, and we need to find $P_2$.

Step3: Rearrange the formula to solve for $P_2$

$P_2=\frac{P_1V_1}{V_2}$

Step4: Substitute the values into the formula

$P_2=\frac{14\times312}{652}$ $P_2=\frac{4368}{652}$ $P_2 = 6.7$ atm

Answer:

$6.7$ atm