gas laws fact sheet\nideal gas law pv = nrt\nideal gas constant r = 8.314 l kpa/mol k or r = 0.0821 l…

gas laws fact sheet\nideal gas law pv = nrt\nideal gas constant r = 8.314 l kpa/mol k or r = 0.0821 l atm/mol k\nstandard atmospheric pressure 1 atm = 101.3 kpa\ncelsius to kelvin conversion k = °c + 273.15\n32\ntype the correct answer in the box. express your answer to three significant figures.\nair is a mixture of many gases. a 25.0 - liter jar of air contains 0.0104 mole of argon at a temperature of 273 k. what is the partial pressure of argon in the jar?\nthe partial pressure of argon in the jar is kilopascal.

gas laws fact sheet\nideal gas law pv = nrt\nideal gas constant r = 8.314 l kpa/mol k or r = 0.0821 l atm/mol k\nstandard atmospheric pressure 1 atm = 101.3 kpa\ncelsius to kelvin conversion k = °c + 273.15\n32\ntype the correct answer in the box. express your answer to three significant figures.\nair is a mixture of many gases. a 25.0 - liter jar of air contains 0.0104 mole of argon at a temperature of 273 k. what is the partial pressure of argon in the jar?\nthe partial pressure of argon in the jar is kilopascal.

Answer

Answer:

$9.42$

Explanation:

Step1: Identify the ideal - gas law formula

$PV = nRT$

Step2: Solve for pressure $P$

$P=\frac{nRT}{V}$

Step3: Substitute the given values

$n = 0.0104$ mol, $R = 8.314\frac{L\cdot kPa}{mol\cdot K}$, $T = 273$ K, $V=25.0$ L $P=\frac{0.0104\ mol\times8.314\frac{L\cdot kPa}{mol\cdot K}\times273\ K}{25.0\ L}$

Step4: Calculate the pressure

$P=\frac{0.0104\times8.314\times273}{25.0}\ kPa$ $P=\frac{0.0104\times2269.722}{25.0}\ kPa$ $P=\frac{23.6051088}{25.0}\ kPa$ $P = 9.44204352\ kPa\approx9.42\ kPa$ (rounded to three significant figures)