give the complete electron configuration for the sulfur ion in problem 6. do not use the noble gas…

give the complete electron configuration for the sulfur ion in problem 6. do not use the noble gas abbreviation. the s ion has __1__ electrons 1s² 2s² 2p⁶ __2__ __3__ a. 10 b. 12 c. 14 d. 16 e. 18 f. 36 g. 38 h. 39 i. 40 j. 3p⁶ k. 3p⁴ l. 3s² m. 3d¹⁰ n. 4d¹ o. 4s² p. 4p⁶ q. 5s² r. 5s⁰ s. 4d⁰ t. 4d³ u. 5s¹ v. 3p⁵

give the complete electron configuration for the sulfur ion in problem 6. do not use the noble gas abbreviation. the s ion has __1__ electrons 1s² 2s² 2p⁶ __2__ __3__ a. 10 b. 12 c. 14 d. 16 e. 18 f. 36 g. 38 h. 39 i. 40 j. 3p⁶ k. 3p⁴ l. 3s² m. 3d¹⁰ n. 4d¹ o. 4s² p. 4p⁶ q. 5s² r. 5s⁰ s. 4d⁰ t. 4d³ u. 5s¹ v. 3p⁵

Answer

Explanation:

Step1: Determine sulfur ion electrons

Sulfur (S) has an atomic number of 16. Sulfur commonly forms a - 2 ion ($S^{2 -}$), so it has 16 + 2=18 electrons.

Step2: Write electron - configuration order

Electrons fill orbitals in the order 1s, 2s, 2p, 3s, 3p. After $1s^{2}2s^{2}2p^{6}$, the next orbitals to fill are 3s and 3p. The 3s orbital can hold 2 electrons and the 3p orbital can hold 6 electrons.

Answer:

  1. E. 18
  2. L. $3s^{2}$
  3. J. $3p^{6}$