give the complete electron configuration for the two gallium ions. do not use the noble gas abbreviation…

give the complete electron configuration for the two gallium ions. do not use the noble gas abbreviation. the oxidation numbers from many, but not all, periodic tables are 1 and 3. one ion completely empties the 4s orbital. use 4s^0 to hold the place for the empty subshell. ga^+1 has __1__ electrons, and the electron configuration is 1s^2 2s^2 2p^6 3s^2 3p^6 __2__ __3__ __4__ ga^+3 has __5__ electrons, and the electron configuration is 1s^2 2s^2 2p^6 3s^2 3p^6 __6__ __7__ __8__ a. 10 b. 12 c. 14 d. 16 e. 18 f. 30 g. 31 h. 28 i. 26 j. 3p^6 k. 3p^4 l. 3s^2 m. 3d^10 n. 4d^1 o. 4s^2 p. 4p^6 q. 5s^2 r. 4p^0 s. 4s^0 t. 4d^3 u. 4p^1 v. 3p^5

give the complete electron configuration for the two gallium ions. do not use the noble gas abbreviation. the oxidation numbers from many, but not all, periodic tables are 1 and 3. one ion completely empties the 4s orbital. use 4s^0 to hold the place for the empty subshell. ga^+1 has __1__ electrons, and the electron configuration is 1s^2 2s^2 2p^6 3s^2 3p^6 __2__ __3__ __4__ ga^+3 has __5__ electrons, and the electron configuration is 1s^2 2s^2 2p^6 3s^2 3p^6 __6__ __7__ __8__ a. 10 b. 12 c. 14 d. 16 e. 18 f. 30 g. 31 h. 28 i. 26 j. 3p^6 k. 3p^4 l. 3s^2 m. 3d^10 n. 4d^1 o. 4s^2 p. 4p^6 q. 5s^2 r. 4p^0 s. 4s^0 t. 4d^3 u. 4p^1 v. 3p^5

Answer

Explanation:

Step1: Determine number of electrons in Ga+1

Gallium (Ga) has 31 electrons. Ga+1 has lost 1 electron, so it has 30 electrons.

Step2: Write electron - configuration for Ga+1

After 1s²2s²2p⁶3s²3p⁶, the next sub - shells are 3d¹⁰4s⁰4p⁰.

Step3: Determine number of electrons in Ga+3

Ga+3 has lost 3 electrons. So it has 28 electrons.

Step4: Write electron - configuration for Ga+3

After 1s²2s²2p⁶3s²3p⁶, the next sub - shells are 3d¹⁰4s⁰4p⁰.

Answer:

  1. F. 30
  2. M. 3d¹⁰
  3. S. 4s⁰
  4. R. 4p⁰
  5. H. 28
  6. M. 3d¹⁰
  7. S. 4s⁰
  8. R. 4p⁰