give the noble gas abbreviated electron configuration for thallium, element 81, using the orbital (box)…

give the noble gas abbreviated electron configuration for thallium, element 81, using the orbital (box) method. tl has __1__ electrons. the noble gas in brackets represents __2__ of the total of __3__ core electrons. __4__ 6__5__ 4__6__ 5__7__ 6__8__

give the noble gas abbreviated electron configuration for thallium, element 81, using the orbital (box) method. tl has __1__ electrons. the noble gas in brackets represents __2__ of the total of __3__ core electrons. __4__ 6__5__ 4__6__ 5__7__ 6__8__

Answer

Explanation:

Step1: Determine number of electrons

Thallium (Tl) has an atomic number of 81, so it has 81 electrons.

Step2: Identify noble - gas core

The noble gas before thallium is xenon (Xe) which has 54 electrons. So the noble gas in brackets represents 54 of the total core electrons.

Step3: Write remaining electron configuration

After the [Xe] core, we need to account for the remaining 81 - 54=27 electrons. The electron - filling order gives us the configuration: [Xe]6s$^2$4f$^{14}$5d$^{10}$6p$^{1}$. - The 6s orbital can hold 2 electrons and is filled first with 2 paired electrons (↑↓). - The 4f sub - shell has 7 orbitals and can hold 14 electrons. It is completely filled with electrons following Hund's rule (electrons first singly occupy orbitals with parallel spins before pairing up). - The 5d sub - shell has 5 orbitals and can hold 10 electrons. It is completely filled with electrons following Hund's rule. - The 6p sub - shell has 3 orbitals and can hold 6 electrons. In thallium, there is 1 electron in the 6p sub - shell, which singly occupies one of the 6p orbitals.

  1. 81
  2. 54
  3. 54
  4. Xe
  5. s$^2$
  6. f$^{14}$
  7. d$^{10}$
  8. p$^{1}$

Answer:

  1. 81
  2. 54
  3. 54
  4. Xe
  5. s$^2$
  6. f$^{14}$
  7. d$^{10}$
  8. p$^{1}$