give the oxidation number of the indicated atoms/ion. na in na₂s

Answer:

D. +1

Explanation:

Step1: Recall oxidation - number rules

In a neutral compound, the sum of oxidation numbers is 0.

Step2: Determine sulfur's oxidation number

Sulfur in sulfides usually has an oxidation number of - 2.

Step3: Let the oxidation number of Na be (x)

For (Na_2S), we have (2x+( - 2)=0).

Step4: Solve for (x)

[ \begin{align*} 2x-2&=0\ 2x&=2\ x& = + 1 \end{align*} ] So the oxidation number of Na in (Na_2S) is +1.