given: 2libr + ba → babr₂ + 2li in this chemical reaction, 325 grams of barium (ba) react completely. how…

given: 2libr + ba → babr₂ + 2li in this chemical reaction, 325 grams of barium (ba) react completely. how many moles of lithium (li) are produced? a. 1.18 mol b. 2.37 mol c. 4.73 mol d. 16.4 mol e. 32.9 mol

given: 2libr + ba → babr₂ + 2li in this chemical reaction, 325 grams of barium (ba) react completely. how many moles of lithium (li) are produced? a. 1.18 mol b. 2.37 mol c. 4.73 mol d. 16.4 mol e. 32.9 mol

Answer

Explanation:

Step1: Calculate moles of barium

The molar - mass of barium (Ba) is (M_{Ba}=137.33\ g/mol). The number of moles of barium (n_{Ba}=\frac{m}{M}), where (m = 325\ g). So (n_{Ba}=\frac{325\ g}{137.33\ g/mol}\approx2.37\ mol).

Step2: Use mole - ratio from the balanced equation

The balanced chemical equation is (2LiBr + Ba\rightarrow BaBr_{2}+2Li). The mole - ratio of (Ba) to (Li) is (1:2). That is, for every 1 mole of (Ba) that reacts, 2 moles of (Li) are produced. If (n_{Ba} = 2.37\ mol), then the number of moles of (Li) produced (n_{Li}=2\times n_{Ba}). (n_{Li}=2\times2.37\ mol = 4.74\ mol\approx4.73\ mol) (due to rounding differences in the previous step).

Answer:

C. 4.73 mol