3. given the following ions, determine the number of protons, electrons, and type of ion a. cu²⁺ b. te²⁻ 4…

Explanation:

Step1: Determine protons for Cu²⁺

Copper (Cu) has atomic number 29. Atomic number = number of protons. So, protons in Cu²⁺ is 29.

Step2: Determine electrons for Cu²⁺

Cu²⁺ has a 2+ charge, meaning it lost 2 electrons. So electrons = 29 - 2=27.

Step3: Determine type of ion for Cu²⁺

Since it has a positive charge, it is a cation.

Step4: Determine protons for Te²⁻

Tellurium (Te) has atomic number 52. So, protons in Te²⁻ is 52.

Step5: Determine electrons for Te²⁻

Te²⁻ has a 2 - charge, meaning it gained 2 electrons. So electrons = 52+2 = 54.

Step6: Determine type of ion for Te²⁻

Since it has a negative charge, it is an anion.

Step7: Draw Bohr model for Argon

Argon has atomic number 18. First shell holds 2 electrons, second shell holds 8 electrons, third shell holds 8 electrons. Draw a nucleus with 18 protons (and neutrons not shown here), and three electron - shells with 2, 8 and 8 electrons respectively.

Answer:

a. Cu²⁺: Protons = 29, Electrons = 27, Type of ion = Cation b. Te²⁻: Protons = 52, Electrons = 54, Type of ion = Anion For Argon, draw a nucleus with 18 protons and three electron - shells with 2, 8 and 8 electrons respectively.