given that the molar mass of nacl is 58.44 g/mol, what is the molarity of a solution that contains 87.75 g…

given that the molar mass of nacl is 58.44 g/mol, what is the molarity of a solution that contains 87.75 g of nacl in 500. ml of solution? use molarity = \\frac{moles of solute}{liters of solution}.\no 0.333 m\no 0.751 m\no 1.50 m\no 3.00 m

given that the molar mass of nacl is 58.44 g/mol, what is the molarity of a solution that contains 87.75 g of nacl in 500. ml of solution? use molarity = \\frac{moles of solute}{liters of solution}.\no 0.333 m\no 0.751 m\no 1.50 m\no 3.00 m

Answer

Explanation:

Step1: Calculate moles of NaCl

$n=\frac{m}{M}$, where $m = 87.75\ g$ and $M=58.44\ g/mol$. So $n=\frac{87.75}{58.44}\approx1.50\ mol$.

Step2: Convert volume to liters

$V = 500\ mL=0.500\ L$.

Step3: Calculate molarity

$Molarity=\frac{n}{V}$, substituting $n = 1.50\ mol$ and $V = 0.500\ L$, we get $Molarity=\frac{1.50}{0.500}=3.00\ M$.

Answer:

D. 3.00 M