in a group assignment, students are required to fill 10 beakers with 0.720 m cacl₂. if the molar mass of…

in a group assignment, students are required to fill 10 beakers with 0.720 m cacl₂. if the molar mass of cacl₂ is 110.98 g/mol and each beaker must have 250. ml of solution, what mass of cacl₂ would be used? use molarity = \\(\\frac{moles of solute}{liters of solution}\\).\n3.13 g\n38.5 g\n200 g\n617 g

in a group assignment, students are required to fill 10 beakers with 0.720 m cacl₂. if the molar mass of cacl₂ is 110.98 g/mol and each beaker must have 250. ml of solution, what mass of cacl₂ would be used? use molarity = \\(\\frac{moles of solute}{liters of solution}\\).\n3.13 g\n38.5 g\n200 g\n617 g

Answer

Explanation:

Step1: Calculate total volume in liters

There are 10 beakers, each with 250 mL. Total volume $V = 10\times250\ mL=2500\ mL$. Convert to liters: $V = 2500\ mL\times\frac{1\ L}{1000\ mL}=2.5\ L$.

Step2: Calculate moles of $CaCl_2$

Use the molarity formula $M=\frac{n}{V}$, where $M = 0.720\ M$ and $V = 2.5\ L$. Rearranging for $n$ (moles), we get $n = M\times V$. So $n=0.720\ mol/L\times2.5\ L = 1.8\ mol$.

Step3: Calculate mass of $CaCl_2$

Given molar - mass of $CaCl_2$ is $110.98\ g/mol$. Use the formula $m=n\times M_m$, where $n = 1.8\ mol$ and $M_m=110.98\ g/mol$. So $m = 1.8\ mol\times110.98\ g/mol\approx200\ g$.

Answer:

200 g