the heat of fusion of hillsideium is 120 j/gram. what is the heat of fusion per mole of hillsideium? (use…

the heat of fusion of hillsideium is 120 j/gram. what is the heat of fusion per mole of hillsideium? (use 60g/mole as the atomic mass of hillsideium)

the heat of fusion of hillsideium is 120 j/gram. what is the heat of fusion per mole of hillsideium? (use 60g/mole as the atomic mass of hillsideium)

Answer

Explanation:

Step1: Identify the conversion factor

We know the heat - of - fusion per gram and the atomic mass (grams per mole).

Step2: Calculate heat of fusion per mole

Multiply heat of fusion per gram by grams per mole. Let $q$ be the heat of fusion per mole, $q_{g}$ be the heat of fusion per gram, and $M$ be the molar mass. The formula is $q = q_{g}\times M$. Given $q_{g}=120\ J/g$ and $M = 60\ g/mol$. Then $q=120\ J/g\times60\ g/mol$. $q = 7200\ J/mol$

Answer:

$7200\ J/mol$